all Python 3Sets (set)function

frozenset.isdisjoint

frozenset

True if the frozenset has no elements in common with the other set.

Syntax

f.isdisjoint(other)

Unlike not (f & other), isdisjoint builds no intermediate set and bails out at the first shared element, which matters on large inputs. Any iterable works as the argument, but a plain iterator gets consumed partially or fully in the process, so you cannot test it again. The empty set is disjoint from everything, itself included: frozenset().isdisjoint(frozenset()) is True.

Examples

print(frozenset({1, 2}).isdisjoint({3, 4}))   # → True
print(frozenset({1, 2}).isdisjoint({2, 3}))   # → False
print(frozenset({1, 2}).isdisjoint([3, 4, 5]))   # → True
print(frozenset('rhythm').isdisjoint('aeiou'))   # → True
print(frozenset({1, 2, 3}).isdisjoint(range(3, 6)))   # → False
print(frozenset().isdisjoint({1, 2}))   # → True

See also

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