all Python 3Sets (set)function

set.issuperset

checking

True if the set contains every element of the other (superset). Operator: >=.

Syntax

s.issuperset(other)

Set comparison is only a partial order: neither {1, 2} nor {2, 3} contains the other, so both directions come back False. That means not a.issuperset(b) does not imply the reverse relation, and calling sorted() or max() on a list of sets yields an arbitrary answer that depends on the starting arrangement.

Examples

print({1, 2, 3}.issuperset({1, 2}))   # → True
print({1, 2}.issuperset({1, 3}))      # → False
print({1, 2, 3} >= {1, 2})            # → True
print({1, 2, 3}.issuperset([1, 3]))   # → True
print({1, 2}.issuperset(set()))       # → True
print({1, 2} >= [1])                  # → TypeError

See also

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